L · EN 10056-1

L 250×250/35

L 250×250/35 is an equal-leg steel angle per EN 10056-1: leg length 250 mm, thickness 35 mm, weight 127.7 kg/m, cross-section area 162.7 cm², moment of inertia Iy = 9191 cm⁴, elastic section modulus Wel,y = 524.9 cm³.

Cross section · mm
yzuvα2502503574.9175.1175.174.9[mm]
250Leg a · mm
35Thickness t · mm
162.70Area A · cm²
127.70Mass G · kg/m
Geometry
Leg length a250.00 mm
Thickness t35.00 mm
Cross-section area A162.700 cm²
Centroid Cx=Cy74.9 mm
Weight G
steel 7850 kg/m³
127.70kg/m
Section properties
Moment of inertia Iy=Iz9 191.000 cm⁴
Section modulus Wel524.900 cm³
Plastic modulus Wpl952.860 cm³
Radius of gyration iy75.20 mm
Principal axes u–v
Iu14 550.000 cm⁴
Iv3 832.000 cm⁴
Reference
Profile standardEN 10056-1
EurocodeEN 1993-1-1 (EC3)

Check to EN 1993-1-1

Work out the utilisation of L 250×250/35 for your design forces

Enter the design loads and the section is checked for bending, shear and compression with flexural buckling.

Bending/ 139.1 kN·m
Shear/ 1.24 MN
Compression/ 2.14 MN
fy265MPaClass3
Resistances and factors
Mc,y,Rd / Mc,z,RdW_el139.1 kN·m / 139.1 kN·m
Vc,z,Rd / Vc,y,RdA_v = 8135 mm²1.24 MN / 1.24 MN
Npl,Rd / Nb,Rd4.31 MN / 2.14 MN
Ncr,y / Ncr,v7.62 MN / 3.18 MN
fyt = 35.0 mm > 16 mm, EN 10025-2265 MPa
γM0 / γM11.00 / 1.00
Curve b · χ0.50

Yield strength is taken from the product standard for the governing thickness, so above 16 mm it is lower than the nominal grade. Simplified checks per EN 1993-1-1, without M+N+V interaction, without lateral-torsional buckling and without web shear buckling. Verify with a full design.

For angles the bending values refer to the axes parallel to the legs, which are not principal axes. A moment about one of them also bends the section about the other, so bending has to be resolved into the principal axes u and v and checked biaxially. Buckling already uses the weaker principal axis v.