L · EN 10056-1

L 250×250/19

L 250×250/19 is an equal-leg steel angle per EN 10056-1: leg length 250 mm, thickness 19 mm, weight 71.7 kg/m, cross-section area 91.4 cm², moment of inertia Iy = 5417 cm⁴, elastic section modulus Wel,y = 298.8 cm³.

Cross section · mm
yzuvα2502501968.7181.3181.368.7[mm]
250Leg a · mm
19Thickness t · mm
91.40Area A · cm²
71.70Mass G · kg/m
Geometry
Leg length a250.00 mm
Thickness t19.00 mm
Cross-section area A91.400 cm²
Centroid Cx=Cy68.7 mm
Weight G
steel 7850 kg/m³
71.70kg/m
Section properties
Moment of inertia Iy=Iz5 417.000 cm⁴
Section modulus Wel298.787 cm³
Plastic modulus Wpl543.880 cm³
Radius of gyration iy77.00 mm
Principal axes u–v
Iu8 622.000 cm⁴
Iv2 212.000 cm⁴
Reference
Profile standardEN 10056-1
EurocodeEN 1993-1-1 (EC3)

Check to EN 1993-1-1

Work out the utilisation of L 250×250/19 for your design forces

Enter the design loads and the section is checked for bending, shear and compression with flexural buckling.

Bending/ —
Shear/ 699.2 kN
Compression/ —

Bending and compression are not available for class 4 sections; effective properties per EN 1993-1-5 are required.

fy265MPaClass4
Resistances and factors
Mc,y,Rd / Mc,z,Rd— / —
Vc,z,Rd / Vc,y,RdA_v = 4570 mm²699.2 kN / 699.2 kN
Npl,Rd / Nb,Rd— / —
Ncr,y / Ncr,v4.49 MN / 1.83 MN
fyt = 19.0 mm > 16 mm, EN 10025-2265 MPa
γM0 / γM11.00 / 1.00
Curve b · χ0.51

Yield strength is taken from the product standard for the governing thickness, so above 16 mm it is lower than the nominal grade. Simplified checks per EN 1993-1-1, without M+N+V interaction, without lateral-torsional buckling and without web shear buckling. Verify with a full design.

For angles the bending values refer to the axes parallel to the legs, which are not principal axes. A moment about one of them also bends the section about the other, so bending has to be resolved into the principal axes u and v and checked biaxially. Buckling already uses the weaker principal axis v.