L · EN 10056-1

L 250×250/25

L 250×250/25 is an equal-leg steel angle per EN 10056-1: leg length 250 mm, thickness 25 mm, weight 93.2 kg/m, cross-section area 118.7 cm², moment of inertia Iy = 6917 cm⁴, elastic section modulus Wel,y = 386.6 cm³.

Cross section · mm
yzuvα2502502571.1178.9178.971.1[mm]
250Leg a · mm
25Thickness t · mm
118.70Area A · cm²
93.20Mass G · kg/m
Geometry
Leg length a250.00 mm
Thickness t25.00 mm
Cross-section area A118.700 cm²
Centroid Cx=Cy71.1 mm
Weight G
steel 7850 kg/m³
93.20kg/m
Section properties
Moment of inertia Iy=Iz6 917.000 cm⁴
Section modulus Wel386.641 cm³
Plastic modulus Wpl702.620 cm³
Radius of gyration iy76.30 mm
Principal axes u–v
Iu11 000.000 cm⁴
Iv2 837.000 cm⁴
Reference
Profile standardEN 10056-1
EurocodeEN 1993-1-1 (EC3)

Check to EN 1993-1-1

Work out the utilisation of L 250×250/25 for your design forces

Enter the design loads and the section is checked for bending, shear and compression with flexural buckling.

Bending/ 102.5 kN·m
Shear/ 908.0 kN
Compression/ 1.58 MN
fy265MPaClass3
Resistances and factors
Mc,y,Rd / Mc,z,RdW_el102.5 kN·m / 102.5 kN·m
Vc,z,Rd / Vc,y,RdA_v = 5935 mm²908.0 kN / 908.0 kN
Npl,Rd / Nb,Rd3.15 MN / 1.58 MN
Ncr,y / Ncr,v5.73 MN / 2.35 MN
fyt = 25.0 mm > 16 mm, EN 10025-2265 MPa
γM0 / γM11.00 / 1.00
Curve b · χ0.50

Yield strength is taken from the product standard for the governing thickness, so above 16 mm it is lower than the nominal grade. Simplified checks per EN 1993-1-1, without M+N+V interaction, without lateral-torsional buckling and without web shear buckling. Verify with a full design.

For angles the bending values refer to the axes parallel to the legs, which are not principal axes. A moment about one of them also bends the section about the other, so bending has to be resolved into the principal axes u and v and checked biaxially. Buckling already uses the weaker principal axis v.