L · EN 10056-1

L 75×75/5

L 75×75/5 is an equal-leg steel angle per EN 10056-1: leg length 75 mm, thickness 5 mm, weight 5.8 kg/m, cross-section area 7.3 cm², moment of inertia Iy = 38.8 cm⁴, elastic section modulus Wel,y = 7.1 cm³.

Cross section · mm
yzuvα7575520.154.954.920.1[mm]
75Leg a · mm
5Thickness t · mm
7.34Area A · cm²
5.80Mass G · kg/m
Geometry
Leg length a75.00 mm
Thickness t5.00 mm
Cross-section area A7.340 cm²
Centroid Cx=Cy20.1 mm
Weight G
steel 7850 kg/m³
5.80kg/m
Section properties
Moment of inertia Iy=Iz38.770 cm⁴
Section modulus Wel7.062 cm³
Plastic modulus Wpl12.920 cm³
Radius of gyration iy23.00 mm
Principal axes u–v
Iu61.590 cm⁴
Iv15.960 cm⁴
Reference
Profile standardEN 10056-1
EurocodeEN 1993-1-1 (EC3)

Check to EN 1993-1-1

Work out the utilisation of L 75×75/5 for your design forces

Enter the design loads and the section is checked for bending, shear and compression with flexural buckling.

Bending/ —
Shear/ 58.3 kN
Compression/ —

Bending and compression are not available for class 4 sections; effective properties per EN 1993-1-5 are required.

Class4
Resistances and factors
Mc,y,Rd / Mc,z,Rd— / —
Vc,z,Rd / Vc,y,RdA_v = 367 mm²58.3 kN / 58.3 kN
Npl,Rd / Nb,Rd— / —
Ncr,y / Ncr,v32.1 kN / 13.2 kN
fyEN 10025-2275 MPa
γM0 / γM11.00 / 1.00
Curve b · χ0.06

Yield strength is taken from the product standard for the governing thickness, so above 16 mm it is lower than the nominal grade. Simplified checks per EN 1993-1-1, without M+N+V interaction, without lateral-torsional buckling and without web shear buckling. Verify with a full design.

For angles the bending values refer to the axes parallel to the legs, which are not principal axes. A moment about one of them also bends the section about the other, so bending has to be resolved into the principal axes u and v and checked biaxially. Buckling already uses the weaker principal axis v.