L · EN 10056-1

L 35×35/5

L 35×35/5 is an equal-leg steel angle per EN 10056-1: leg length 35 mm, thickness 5 mm, weight 2.6 kg/m, cross-section area 3.3 cm², moment of inertia Iy = 3.6 cm⁴, elastic section modulus Wel,y = 1.4 cm³.

Cross section · mm
yzuvα3535510.424.624.610.4[mm]
35Leg a · mm
5Thickness t · mm
3.28Area A · cm²
2.60Mass G · kg/m
Geometry
Leg length a35.00 mm
Thickness t5.00 mm
Cross-section area A3.280 cm²
Centroid Cx=Cy10.4 mm
Weight G
steel 7850 kg/m³
2.60kg/m
Section properties
Moment of inertia Iy=Iz3.560 cm⁴
Section modulus Wel1.447 cm³
Plastic modulus Wpl2.650 cm³
Radius of gyration iy10.40 mm
Principal axes u–v
Iu5.640 cm⁴
Iv1.490 cm⁴
Reference
Profile standardEN 10056-1
EurocodeEN 1993-1-1 (EC3)

Check to EN 1993-1-1

Work out the utilisation of L 35×35/5 for your design forces

Enter the design loads and the section is checked for bending, shear and compression with flexural buckling.

Bending/ 0.4 kN·m
Shear/ 26.0 kN
Compression/ 1.2 kN
Class3
Resistances and factors
Mc,y,Rd / Mc,z,RdW_el0.4 kN·m / 0.4 kN·m
Vc,z,Rd / Vc,y,RdA_v = 164 mm²26.0 kN / 26.0 kN
Npl,Rd / Nb,Rd90.2 kN / 1.2 kN
Ncr,y / Ncr,v3.0 kN / 1.2 kN
fyEN 10025-2275 MPa
γM0 / γM11.00 / 1.00
Curve b · χ0.01

Yield strength is taken from the product standard for the governing thickness, so above 16 mm it is lower than the nominal grade. Simplified checks per EN 1993-1-1, without M+N+V interaction, without lateral-torsional buckling and without web shear buckling. Verify with a full design.

For angles the bending values refer to the axes parallel to the legs, which are not principal axes. A moment about one of them also bends the section about the other, so bending has to be resolved into the principal axes u and v and checked biaxially. Buckling already uses the weaker principal axis v.